Following code works just fine:
var Q = require('q');
function async_f1(callback) {
var deferred = Q.defer();
setTimeout(function() {
deferred.resolve("Async function 1...");
}, 1000);
return deferred.promise;
}
function async_f2(callback) {
var deferred = Q.defer();
setTimeout(function() {
deferred.resolve("Async function 2!...");
}, 1000);
return deferred.promise;
}
function async_f3(callback) {
var deferred = Q.defer();
setTimeout(function() {
deferred.resolve("Second async function 3!...");
}, 1000);
return deferred.promise;
}
Q.spread([async_f1(), async_f2(), async_f3()], function(a, b, c) {
console.log(a, b, c);
})
But I really don't think it's the best way to convert async functions into promises. There are a lot of repeatings of defer stuff. I've read some about Q.denodeify feature but I was unable to implement it.
Could you show me how it is done in this particular case?
Thank you
Aucun commentaire:
Enregistrer un commentaire